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Every std::string implementation has a pointer to the raw characters in it somewhere The string class is an instantiation of the basic_string class template that uses char (i.e., bytes) as its character type, with its default char_traits and allocator types (see basic_string for more info on the template). For g++ 4.x, that pointer is at offset 0 into the string

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If you know that the string resides at e.g By default it's being abbreviated, how do i force gdb to print the whole string? 0x7fffffffda88, then print *(char**)0x7fffffffda88 is what you need.

Instead of std::string st = c:\\\\program files\\\\myfile.txt

That's because the `<string>` header is using some trickery that hides the other data in memory that resides before the string data. Here is how a C ++std::string looks without a pretty-printer: (gdb) print s $1 = { static npos = 4294967295, _M_dataplus = { <std::allocator<char>> = { <__gnu_cxx::new_allocator<char>> = { <No data fields>}, <No data fields> }, members of std::basic_string<char, std::char_traits<char>, std::allocator<char> >::_Alloc_hider: _M_p = 0x804a014. The class is dependent neither on the character type nor on the nature of operations on that type Currently std::string variables are shown as stl containers, but it would be quite beneficial if we could see actual contents as well, either during hovering over that var or by putting it at watch.