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Because control structures in lua only consider nil and false to be false, and anything else to be true, this will always enter the if statement, which is not what you want either Both of these perform a lua pattern search on the string to find matches. There is no way that you can use binary operators like those provided in programming languages to compare a single variable to a list of values.

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The lua authors felt that continue was only one of a number of possible new control flow mechanisms (the fact that it cannot work with the scope rules of repeat/until was a secondary factor.) 167 there are 2 options to find matching text Why are you finishing each lua script with additional end

Just remove these end s.

In general, if you want a switch statement in lua, what you ought to be doing is building a table For your simple case of choice that could be 1, 2, or fail, a simple if statement with a few conditions is sufficient. I am wondering if there is a way of getting the path to the currently executing lua script file This is specifically not the current working directory, which could be entirely different

So the key associated with joe in the table is 2 (lua indices always start at 1) Therefore, you need a for loop that counts from 1 to 3, which you get You use the count variable to access the element from the table However, this has a flaw

What happens if you remove one of the elements from the list?

As for the pure lua solutions, let me share this small benchmark, i've made It covers every provided answer to this date and adds a few optimizations Still, the basic thing to consider is How many times you'll need to iterate over characters in string

If the answer is once, than you should look up first part of the banchmark (raw speed). I have seen the hash character '#' being added to the front of variables a lot in lua 45 if you are splitting a string in lua, you should try the string.gmatch () or string.sub () methods Use the string.sub () method if you know the index you wish to split the string at, or use the string.gmatch () if you will parse the string to find the location to split the string at

Example using string.gmatch () from lua 5.1 reference manual: