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The class template std::future provides a mechanism to access the result of asynchronous operations When i'm managing some async An asynchronous operation (created via std::async, std::packaged_task, or std::promise) can provide a std::future object to the creator of that asynchronous operation

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The creator of the asynchronous operation can then use a variety of methods to query, wait for, or extract a value from the std. Obviously, they have different methods and stuff, but what is the actual use case The get member function waits (by calling wait ()) until the shared state is ready, then retrieves the value stored in the shared state (if any)

Right after calling this function, valid () is false

If valid () is false before the call to this function, the behavior is undefined. If the future is the result of a call to std::async that used lazy evaluation, this function returns immediately without waiting This function may block for longer than timeout_duration due to scheduling or resource contention delays The standard recommends that a steady clock is used to measure the duration.

Int64 if i understand the warning correctly, the object dtype is downcast to int64 Perhaps pandas wants me to do this explicitly, but i don't see how i could downcast a string to a numerical type before the replacement happens. Checks if the future refers to a shared state Returned by std::promise::get_future (), std::packaged_task::get_future () or std::async ()) until the first time get () or share () is called

Specifies state of a future as returned by wait_for and wait_until functions of std::future and std::shared_future

Unpin + future + ?sized, boxed futures only implement the future trait when the future inside the box implements unpin Since your function doesn't guarantee that the returned future implements unpin, your return value will be considered to not implement future You'll not able to await it because your type is basically not a future. A future statement is a directive to the compiler that a particular module should be compiled using syntax or semantics that will be available in a specified future release of python

The future statement is intended to ease migration to future versions of python that introduce incompatible changes to the language If the future is the result of a call to async that used lazy evaluation, this function returns immediately without waiting The behavior is undefined if valid () is false before the call to this function, or clock does not meet the clock requirements I'm confusing myself with difference between a std::future and a std::promise